- * '!', for a total of 92 symbols. In order to express 48x48=2304
- * bits, we need a total of 354 digits, as given by:
- * ceil(lg_92(2^2304)) = 354
+ * '!', for a total of 94 symbols. In order to express
+ * 48x48*2=8*XFACE_MAX_WORDS=4608
+ * bits, we need a total of 704 digits, as given by:
+ * ceil(lg_94(2^4608)) = 704