/*
* Image is encoded as a big integer, using characters from '~' to
- * '!', for a total of 92 symbols. In order to express 48x48=2304
- * bits, we need a total of 354 digits, as given by:
- * ceil(lg_92(2^2304)) = 354
+ * '!', for a total of 94 symbols. In order to express
+ * 48x48*2=8*XFACE_MAX_WORDS=4608
+ * bits, we need a total of 704 digits, as given by:
+ * ceil(lg_94(2^4608)) = 704
*/
-#define XFACE_MAX_DIGITS 354
+#define XFACE_MAX_DIGITS 704
#define XFACE_BITSPERWORD 8
#define XFACE_WORDCARRY (1 << XFACE_BITSPERWORD)
* The probability of the data determines the range of possible encodings.
* Offset gives the first possible encoding of the range. */
typedef struct {
- int range;
- int offset;
+ uint8_t range;
+ uint8_t offset;
} ProbRange;
extern const ProbRange ff_xface_probranges_per_level[4][3];